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T dv=P ng sut trong ct thp ng sut trc, khi Lc dc ngoi : Nu =-Mu = Mmen cc hn ti mt ct cch gi "dv"DmG lan can Mcb = Tay vn Mrl =To dc Mpv = B tng CIP Mcip=> Din tch thp ng sut trc v pha ko un ca cu kin Th ln u : ng sut ct1. S liu chungb=3 Sc khng ct ca thnh phn b tng trong (1): Dng Vn= % Ct thp ai s phi b tr khi : Nu Vu < 0.1 f'c bv dv  Nu Vu > 0.1 f'c bv dv $th : S < 0.8 dv < 600 mm. 'th : S < 0.4 dv < 300 mm. " S dng khong cch ti a lS Khi thit k i hi ct thp chu ct th din tch ct thp s khng nh hn:$gii hn chy ca ct thp ai (Mpa)Vi s= Av(B tr)= Din tch thp ng sut trc > Creep 4 to days pha chu ko ca cu kinUnCt Thay vo :F Ct thp dc b tr mi mt ct phi tho mn phng trnh sau:trng lng dmtrng lng bn lin hptrng lng g chn lan cantrng lng tay vntrng lng lp ph mt cung sut trc Mmen unModunn hi qun tnhMsl=C Vic tnh ton vng v vng da trn c s mdun n hi  v tui ca b tng.F vng tc thi s c tnh cho tt c cc tc ng ca tnh ti v lc d ng lc."d ng lc v trng lng bn thn Tnh ti giai on 2 v hot tiMpa sau 28 ngy: Bng tng hp mmen un, moun n hi v mmen qun tnhB Trong thc t tnh ton vng do tnh ti phn 2 v hot ti cng EI s tng ln 10%.) vng do d ng lc s c tnh td ng lc ti im truyn+Hiu qu d ng lc sau tt c cc mt mt Pe = ntao*Aps*(0,78*fpu-LOSS)=: H s c hiu d ng lc v ct thp thng v lc d ng lc Vng xungVng ln: vng lu di c th ly bng 4 ln vng tc thi7 nu tnh ton da trn c s tng mmen qun tnh Ig vng lu di+ vng lu di ti thi im 1000 ngy H s t bin:' Vi Th tch/ Din tch mt =  m trung bnh,Vng ln ngay khi truyn ng sut (ct thp)PCng Do Xe ti Do Xe hai trc vng do xe ti: vng ca 25 % xe ti= + Ln => vng gii hn ca hot ti l 1/1000 * (khu nhp).%Cu dm bn rng btct ng sut trc "Cu dm bn rng b tng ct thp 8Cu dm bn rng btct DL thit k theo AASHTO LRFD-19985Cu dm bn rng BTCT thit k theo AASHTO LRFD-19985.5.1 Live Loads :5.5.2 Dead Loads5.6 Loads and Load Combinations=Z(LRFD 5.7.3.4-1)&Aps fps ( dp-a/2) + As fy (ds - a/2)ds=As' =dedc=A = =Z =N/mmN/mm2< 0.6fy = at 1/4 L0Hiu qu tc ng tnh ca xe ti hoc xe 2 trc$S c tng thm mt lng nh sau:Cho cc b phn cuMi ni bn mt cuCho TTGH mi v ginPti trng ng cho php khng p dng cho ti trng ngi i b v ti trng lnXe ti (xe 2 trc): + Momen : + Lc ct :Ti trng ln: ng nh hng mmen v lc ct Ti gia nhp ti trng MomenLc ctLn thit k Mt ct cch gi dv =Mt ct ti giCho dm trong v dm ngoiCho dm ngoi bn tri v phi Cho dm trong Giai on 1Trng lng dm Giai on 2Tay vnG chn lancanTo dc Bn lin hpB tng lp yMt ctG chn lan can Din tch DAH Lp to dcHot ti dv t giGiDm bin,Bng tng hp mmen v lc ct trn dm bin-Bng tng hp mmen v lc ct trn dm trongBng mmen xon dm bin1(Xe ti hay xe 2 trc )*(1+IM) *D + ti trng lnTi gi e-Lch tmQ Mi thnh phn hoc lin kt s phi tho mn cng thc sau ng vi mi TTGH: H s iu chnh ti trng ' i vi dm b tng ct thp thng. = 0.03L (cho nhp gin n), ; = 1.2( L +3000)/30 (cho nhp gin n), / i vi dm b tng ct thp ng sut trc5 chiu cao ti thiu (k c bn lin hp) nh sau:Chiu cao dm ti thiu Thng thng h ~ 0.045L Ngi lp: Ngi tnh:O Cc yu cu v tnh do c tho mn vi mt kt cu c th sc khngS ca lin kt khng qu 1,3 ln hiu ng lc ln nht do tc ng khng n hi 4 ca cc cu kin lin k tc ng ln lin kt J Cc b phn hoc cu kin chnh m s h hng ca chng khng gy nnP sp cu c coi l khng c nguy c h hng v h kt cu lin quan l dn Cc cu c phn loi da trn cc yu cu x hi / s sng st v/hoc cc yu cu v an ninh quc phng.G H s xt n tnh do ch p dng cho trng thi gii hn cng F H s xt n tnh d ch p dng cho trng thi gii hn cng l H s xt n tm quan trng khi khai thc ch p dng cho trng thi gii hn cng v TTGH c bit)H s iu chnh ti trng trong cc TTGHCng c bitS dngMi H s sc khng/ Khi tnh kh nng chu un kt cu BTCT thng, Khi tnh kh nng chu un kt cu BTCT DL Khi tnh kh nng chu ctW Trng thi gii hn s dng ch gii hn v ng sut, bin dng v b rng vt nt.T hp cc h s.6.1.2 T hp ti trng v h s ti trng 6 S dng-I 1.0 {1.0 DC + 1.0 LL}6 S dng-III 1.0 {1.0 DC + 0.8 LL} S dng I S dng IIIO S dng-I : T hp ti trng lin quan n khai thc thng thng ca cuY S dng-III : T hp ti trng lin quan n ng sut ko ca kt cu ng sut trc H s ti trng :Lp ph mt cu ( Asphalt)" Cc cu kin v b phn lin quan Hot ti (TTGH S dng-I ) Hot ti (TTGH S dng-III )R Hiu ng lc do nhit , co ngt v t bin trong dm gin n coi nh bng 0D Hiu ng lc do gradient nhit, gi v ma st gi khng tnh n!6.2 Thng thi gii hn cng M Trng thi gii hn cng xem xt m bo yu cu bn v n nh86.2.1 Cc h s iu chnh ti trng c th p dng86.1.1 Cc h s iu chnh ti trng c th p dng.6.2.2 T hp ti trng v h s ti trng Y Cng - I : T hp ti trng c bn xe s dng thng thng ca cu, khng xt gi!Cc cu kin v b phn lin quan Qui c du- ng sut ko+ ng sut nnKt qu ng sut ti gia nhpGi tr ng sut dounMmen Mmen qtnh chng unng sut do mmen Trng lngdmbn lhp g lan can Lp ph mcCng: Hot ti Hot ti Ml = Hot ti > ng sut ko trong vng nn trc khng xut hin vt nt<0,95m3Mdo=fdo'fdoMcb=Cho ct v xon3 Vn ,Tn = Sc khng ct v xon danh nhH s iu chnh ti trngU Chiu cao chu ct c hiu c ly bng khong cch gia hp lc ko v lc nn ] do un vi trc trung ha, nhng khng cn ly t hn tr s ln hn ca 0.9de hoc 0.72h, hoc khong cch dv t mt trong ca gi.3 v vy, s dng khong cch dv tnh lc ct. dv=Lc ct c hiu:( y Ao= 0.85 Aoh)6 Sc khng ct danh nh s ly gi tr nh hn caVi:8 Vc = Sc khng ct ca thnh phn b tng 9 Vs = Sc khng ct ca thnh phn ct thp chu ctH Vp = Thnh phn ng sut trc c hiu trn hng lc ct tc dng& kN ( y khng s dng tao cp xin)# v khong cch vt nt.X Lc ct l nguyn nhn gy ko trong ct thp dc. Vi mt ct chn s cng ny 2.3 Thp ng sut trc M S dng tao thp 7 si, ng knh danh nh 12.7mm loi t trng thp/ theo tiu chun AASHTO M-203 (ASTM A416-85)Cng cc hn Gii hn chy Modul n hiU b tng b nt cho, khi cc vt nt tr ln rng hn, ng sut c th c truyn ny s gim i.< W Vi cc cu kin c ct thp ngang, c gi nh l cc vt nt cho s cch nhau khong 300mm.J ng sut nn trong b tng sau tt cR cc mt mt ti trng tm mt ct do hot tiI ng sut trc c hiu ti trng tmT ct thp ng sut trc sau tt c cc mt mt fcb'fcbMrl=frl'frlMpv=fpv'fpvMl=fl'flMl=0,8Ml  fc= 0.45 f'c (Mpa) fc= 0.60 f'c (Mpa)$ As = fd0g = Md0 eo / Igo =P/Ago + P eo/Sb =, fd0g = Md0 eo / Igo/ Pe =n Aps(0.78fpu-LOSS)fpi = 0.7 fpu =Pi =n Aps fpi=xnN Mpa  xn N& fb = fd0 + fd1 + fcb + frl + fpv + fl fb - ft = n = StrandsPi = n Aps fpiN=MNfcgp = fd0g + fps fg(top) =fc =0.45 f'c =fc = 0.60 f'c =As (Mpa)D =  Mpafpj = 0.78 fpu =fpy = 0.90 fpu =(LRFD 5.7.3.6.2)(LRFD 5.4.2.3.2-1)(LRFD 5.4.2.3.2-2)Httikc(Fig. 5.4.2.3.2-1)f =NgyGiChiu di ton b Chiu di dm Khu nhpB rng lm vic cuGc xinKhong cch dm S ln thit k:Lp ph mt cu To phngMt ct ngang cu 2. Vt liu 2.1 B tng 2.1.1 Dm BTCT c sn:cng b tng tui 28 ngyT trng b tng (khi tnh Ec)/ (Khi tnh tnh ti)M un n hiM un chng ct H s Poisson2.1.2 bn b tng sau' " T s mun n hi ca dm/ bn2.2 Ct thp thngE sGii hn chy thp dc ch'Gii hn chy tt c cc loi thp khc xe 2 trc#ti trng trc v ti trng phn bXe titi trng phn b Xe 2 trcI vng gii hn ca ti trng xe ti l 1/1000 khu tnh ton Chn chiu cao dmM B dy ti thiu lp b tng bo v ct thp ch phi theo iu kin sau:Th trnTh diYKhi c lp cch nc v to phng th b dy b tng ti thiu c th gim xung l 35mm.7 Giai on I ( Dm gin n) : Trng lng bn thn8 Giai on II : Trng lng bn lin hp (nu c)D Giai on III : Trng lng lp mt cu, lan can, g chn ...4 Kt cu cu s c phn tch theo 3 giai on : Kch thcTnh c trnghnh hcmt ct Cng 1Cng 2c trng hnh hc khng l.hpMt ct lin hpn v Din tchMmen qun tnhTrng tm n th diC.G n th trn dmC.G n th trn bnMmen tnh vi th di Stnh vi th trn dm Stnh vi th trn bn H s phn b cho mmen!H s phn b mmen cho dm trongb = B rng dmL=Khu nhpNb= S lng dm trn MCN :Ip =Mmen qun tnh cc!H s phn b mmen cho dm ngoi H s phn b cho lc ct#H s phn b lc ct cho dm trong#H s phn b lc ct cho dm ngoi t =N.mme= fg(top) = fci = 0.60f'ci = SAs= S =f=Tandem$=z max Q, FQ+ = -FQ- of inf.  *=z max M, FM of inf.! "813. Control of cracking by distribution of reinforcementAASHTO HL93 Lane LoadAASHTO HL93 Truck Load+ Tao Thp t chng thp c s dng:@ Gi tr mt mt ng sut ca thp chng thp s c gim(22TCN 272-01 ,Iu 5.7.3.2) (22TCN 272-01 ,Iu 5.7.3.1.1-1) (22TCN 272-01 ,Iu 5.7.3.1.1-2) (22TCN 272-01 ,Iu 5.7.3.1.1-4) (22TCN 272-01 ,Iu 5.7.3.2.1-1) (22TCN 272-01 ,Iu 5.7.3.3.1-1) (22TCN 272-01 ,Iu 5.7.3.3.1-2)(22TCN 272-01 ,Iu 5.7.3.3.2)(22TCN 272-01 ,Iu 5.4.2.6)(22TCN 272-01 ,Iu 5.11.4.1-1)(22TCN 272-01 ,Iu 5.8.1.1)(22TCN 272-01 ,Iu 5.8.2.1)(22TCN 272-01 ,Iu 5.5.4.2)(22TCN 272-01 ,Iu 1.3.1)(22TCN 272-01 ,Iu 3.4.1)(22TCN 272-01 ,Iu 5.8.2.7)(22TCN 272-01 ,Iu 5.8.3.3-1)(22TCN 272-01 ,Iu 5.8.3.3-2)(22TCN 272-01 ,Iu 5.8.3.3-3)(22TCN 272-01 ,Iu 5.8.3.3-4) (22TCN 272-01 ,Iu 5.8.3.4.2-2) (22TCN 272-01 ,Iu 5.8.3.4.2-1) (22TCN 272-01 ,Iu 5.8.3.4.2-3)(22TCN 272-01 ,Iu 5.8.2.4-1)(22TCN 272-01 ,Iu 5.8.2.5)(22TCN 272-01 ,Iu 5.8.3.6.3)(22TCN 272-01 ,Iu 3.6.1.3.2)(22TCN 272-01 ,Iu 5.4.2.4)(22TCN 272-01 ,Iu 5.4.2.5)(22TCN 272-01 ,Iu 5.4.4.1-1)(22TCN 272-01 ,Iu 2.5.2.6.2)(22TCN 272-01 ,Iu 2.5.2.6.3)(22TCN 272-01 ,Iu 5.12.3)(22TCN 272-01 ,Iu 3.6.1.2)!(22TCN 272-01 ,Bng 4.6.2.2.2b-1)!(22TCN 272-01 ,Bng 4.6.2.2.2d-1)!(22TCN 272-01 ,Bng 4.6.2.2.3a-1)!(22TCN 272-01 ,Bng 4.6.2.2.3b-1)(22TCN 272-01 ,Iu 3.6.2)(22TCN 272-01 ,Iu 1.3.2.1-1)(22TCN 272-01 ,Iu 1.3.2.1-2)(22TCN 272-01 ,Iu 1.3)(22TCN 272-01 ,Bng 3.4.1-1)(22TCN 272-01 ,Iu 5.9.4.2.2)(22TCN 272-01 ,Iu 5.9.4.2.1)(22TCN 272-01 ,Bng 5.9.3-1)(22TCN 272-01 ,Iu 5.9.5.3)(22TCN 272-01 ,Bng 5.9.5.3-1)(22TCN 272-01 ,Iu 5.9.5.2.3)(22TCN 272-01 ,Iu 5.9.5.4.4b)#5.6.3 Mt mt do ct thp t chng t chng thpU thi gian xp x 1 ngy l hp l khi tnh mt mt ng sut do t chng ct thp (bn ny l y nht n ngy 8-7-200414. SHEAR AND TORSION DESIGN14.1 Design Procedure!14.2 Shear and Torsion Strength&14.3 Factored Shear Force and Torsion14.4 Shear Force Effect314.4.1 Dead Load And live load shear & Torsion$14.4.2 Nominal shear resistance#14.4.3 required shear strength814.4.4. MAXIMUM TRANSVERSE SHEAR REINFORCEMENT SPACING .14.4.5. MINIMUM TRANSVERSE SHEAR REINFORCEMENT 14.5 Longitudinal Reinforcement15. deflection and camber+15.1 Deflection Due To Prestressing Forces15.3 Deflection at Transfer"15.2 Deflection Due To Dead Loads,15.2.1 defection due to weight of girder*15.2.2 defection due to weight of curb-15.2.3 defection due to weight of Railing#15.2.4 defection due to weight !15.5 Deflection Due to Live LoadDxDyS lk/c l415.4 Deflection Due to All Dead Loads And Prestress de =!fps = fpu (1-k C/dp) < fpu = k = 2 ( 1.04 - fpy/fpu ) =Aps =b = dp=mm c =fps = fpu ( 1-k c/dp )= Mpa < fpu= th xa nht ca mt ct " i vi th xa nht ca mt ct .Mpa ng sut th xa nht do ng sut trc )Mmen do tnh ti mt ct khng lin hp O Tao cp ng sut trc phi c dnh bm vt qu mt ct nguy him vi, chiu di trin khai (mm) c tnh theo: Thay vo: ld =O Cc cu kin phi c cu to sao cho ng sut ko trong ct thp thng  fsa khng c vt qu:'5.5. ng sut trong giai on khai thc$5.6. ng sut ti thi im ct thp,Chiu dy lp b tng tnh t th ngoi cng(chu ko n trng tm ct thp gn nht6 song song vi trc trung ha, chia cho s lng thanh<Din tch b tng c bao bi mt ct ngang v ng thng B rng bu dm= Vi cc cu kin mt tip xc vi mi trng khc nghit:mm =[ M hnh tnh truyn thng vi gi thit mt ct vn phng sau khi t ti vn hp thc,T cc thnh phn c th thit k theo mt trong 2 cch l m hnh chng-ging hoc m hnh mt ct phng.U Ni m khong cch t im lc ct bng 0 n mt gi nh hn 2d, hoc l cc cu] kin trong ti trng tp trung gy ra ln hn 1/2 lc ct gi gn hn 2d tnh t mt ] gi th c th coi chng l loi dm cao v m hnh tnh ton chng-ging s c p dng:Mn=N.mm=Mr = , c/de < 0.42 + de = (Aps fps dp+As fy ds)/(Aps fps+As fy)N compression fiber to the centroid of the tensile force in4 the tensile reinforcement (mm).c/de =  (LRFD 1.3) (LRFD 3.4.1)IxxIyyh3 LOSS = 270(1- 0.15*(f'c-41)/41)+41PPR kN-m = Mr'Mcr = (fr + fpe) Sc - M(DL) (Sc/Sb - 1)Sc=Sb= fpe =f'c =M(DL) =kN-m< Mcr =MN-m=fps =fpe =0.78 fpu -LOSS =db =d= Since L/2 =  Date Sign: CheckN.D.T 2. MATERIAL 2.1 Concrete%2.1.1 Precast Prestressed Girder#2.1.2 C.I.P Concrete for Slab2.2 Reinforcing Steel2.3 Prestressing Steel 3. LIVE LOAD dv = de - a/2 mm 0.9de =-> dv=0.72h =  Vu = Tu =Vn = Vc + Vs + VpVn = 0.25 f'c bv dv + Vp0.002  fpo = fpe + fpc Ep/Ecfpc =Mpa Md1=% fpe' = Pe / Ago + Mpe / St$ fpe = Pe / Ago + Mpe / Sbfp = Pj/Ago + Mpj/Stfp = Pj/Ago - Mpj/Sb = fp = Pj/Ago - Mpj/Sb fpe = 0.78 fpu - LOSS = fpo = fpo = Mdo = abcdeBsBtBmBbAy Aps = n*Aps =fpe = 0.80 fpy = fy = 0.9 fpu =R Vi ti trng s dng bao gm c ti trng xe, ng sut ko trong cc b phn 7Vi cc cu kin c cc b thp ng sut trc dnh bm,Cu kin trong iu kin n mn nghim trng$Di tc dng ti trng thng xuynJDi tc dng ti trng thng xuyn v nht thi trong vn chuyn cu lp; Vi: Cng b tng khi truyn ng sut : f'ci = 1 Modul n hi b tng : Eci = - Modul n hi thp : Ep = ti mt ct mmen ln nht` fcgp = Tng ng sut b tng do lc d ng lc v trng lng bn thn ti trng tm tao cp1 c ly bng 0.70fpu cho thp t trng thp. ( n= s tao thp )z i vi cc cu kin ko trc ca thit k thng thng fcgp c th tnh trn c s ng sut ca thp ng sut trc a Ti thi im ny, gi tr lc to ng sut trc yu cu cha xc nh, v vy s hp l hnTng cc mt mt ng sut =& Lc to ng sut trc mm2 / tao( Din tch 1 tao cp, Aps = &P = n x Aps x (0.78 x 1860 - loss) &P = n x Aps x (0.78 x fpu - LOSS ) ' Tng cng ng sut th di dm binkhng c vt quMpa. O C ngha l ng sut nn trc trong qu trnh to ng sut trc cui dm& Tnh : P / Ago + P x eo / Sb = - Th ln th nht :& Trng tm ca tt c cc b thp ti Ti trng tm mt ct Ti th di dm:Chn:tao - Th ln th hai : Tng s tao = ) Trng tm cc tao cp ti th di dm0 Trng tm tt c cc tao cp ti th di dm1 Trng tm tt c cc tao cp ti trng tm dmU Mt mt do co ngn n hi ca b tng trong cc b phn ko trc phi ly bng:1 Mt mt co ngn n hi (Ep/Eci )fcgp =7 Lc d ng lc : P = n Aps(0.78fpu-LOSS)) = n x Aps x (0.78 x fpu - tng mt mt)Tnh :. Hiu qu lc P/S sau tt c cc mt mt :Mpa Cho dm binDo ti trng thng xuyn:*Do ti trng thng xuyn v ti trng xe:fg(b) = Bng ng sut gia nhp dm binTnh ti- Dm - Bn mt cu- G chn lan can - Tay vn- To dc+Asphal+CIP d ng lc S-I=(ng sut do t trng + d ng lc .)#S-II=(ng sut do tt c ti trng  + d ng lc .)Kim tra: ng sut cho phpR D ng lc c tha nhn bin i tuyn tnh t 0 ti u tao cp n gi tr0 ln nht ti cui chiu di truyn ng sut D Chiu di truyn ng sut c th ly bng 60 x (ng knh tao).ng knh tao =e Mt mt ng sut ti im truyn ch bao gm nn ngn n hi ca b tng v t trng ca tao cp1Cng b tng khi truyn ng sut : f'ci = [ Mt mt do co ngn n hi ca b tng trong cc cu kin ng sut trc phi ly bng:k Cc tao cp c cng trong thi gian ngn trc khi b tng v lc d ng lc s truyn cho b tng $ trong thi gian ngn sau khi ct. ti im truynngy/tao s c bc u (ti im truyn ng sut )! Tng lc d ng lc , Pj =! Lc cho 1 tao, P/n = Khong cch n gi "D" Th di, Mg / Sb =  Th trn, Mg / St =< Gii hn ng sut ko trong din tch ct thp dnh bm: fg(bot) = 9 Gii hn ng sut nn trong cu kin ng sut trc :$Bng ng sut cch gi 1 khong "D" Th trn (Mpa)Th di (Mpa)Do trng lng bn thnDo ng sut trc ng sut cho php thanhC tao s c bc u thanh ti 3.5m ti im truyn ng sut trc C tao s c bc u thanh ti 1.0m ti im truyn ng sut trc (Bng ng sut cch gi 1 khong "1.0+D" Hiu ng ti, Q =Mmen un, Mu =[ Trong thc tin thit k, coi ng sut phn b trn 1 khi ch nht tng ng cnh l nhng khng nh hn 0.65" Vi f'c <= 28 Mpa V tr trc trung ho:B Vi mt ct hnh ch nht: c = (Aps fpu + As fy - As' fy' ) B tr ct thp thng:mm2 &Din tch ct thp trong vng chu koB rng cnh chu nn#khong cch xa nht t th chu nn#ti trng tm tao cp vng chu ko+ti trng tm ct thp thng vng chu ko Hay: Sc khng un danh nh:Q Sc khng un danh nh ca mt ct hnh ch nht c th tnh theo cng thc: Sc khng un:^ Lng ct thp ti a ng sut trc v khng ng sut trc s c kim tra vi dki sau: Trong : y:9 c = khong cch t th chu nn xa nht0 ti trc trng trng tm =& =Chiu cao lm vic tng ng t th ) chu nn xa nht ti trng tm lc ko trong ct thp chu ko (mm)K Lng ct thp ng sut trc v ct thp thng phi pht trin @ sc khng un tnh ton Mr, t nht bng 1.2 ln cng nt Kim tra dm bin v / f'c=Vn =Vn = Vc + Vs + Vp = (1)% Vn=0.25 f'c bv dv+Vp =(2)+4. prestressed concrete bridge requirement Asphalt Mas = f'cifpu0.9fpuEpfpy =LbLgLsWbedegSgf'c M Design M of Lane Q Design Q of Lane L / 4L / 2Vu = 0.1 f'c bv dv =kN =Vu$ Av = 0.083sqrt (f'c) bv s/fyfy=Av=mm2mm2  Mpa mm2 mm = f'c = Ec =Mpa at 4 days n=Ec/Eci=Mpvl=Mp=es =fps Av fy Mu dv ff s Nu Vu TuVsVp Aps kf = 62 / (42 + f'c) =t =% BDM6.1.2C-2V The prestressed girder deflection is calculated using the modified creep equation,: which correlate well with data from field measurements:Ct =f 0.152 Ln ( t +1 )days,3. Yu cu k thut dm BTCT ng sut trc 3.1 Ch tiu vng33.2 Ch tiu v t s gia chiu cao / khu nhp3.3 B dy b tng bo v4. c trng mt ct ngang 4.1 Kch thc mt ct ngang dm4.2 Kt qu tnh THH4. Tnh ni lc4.1 Tnh ti : 4.2. Hot ti4.2.1 Hot ti thit k :"4.2.2 H s phn b ngang hot ti-4.2.3 Ti trng ng cho php (lc xung kch)!trng i hc giao thng vn tithuyt minh tnh ton fpj =0.75 fpu =" fpt = 0.70 fpu =KNi lc do hot ti = (Xe ti hay xe 2 trc )*(1+IM) *D + ti trng ln4.2.4 Ni lc do Hot ti :4.3 T hp ti trng  Cng:5. Trng thi gii hn s dng:5.1. Khi nim chung5.2. Cc h s1 vi mc ch kim tra nt5.3. Tnh ton ng sut'5.4. Xc nh s lng b cp cn thit"5.4.1.1 gii hn ng sut ko25.4.1.2 gii hn ng sut nn sau khi mt mt/5.4.3 c lng gn ng cc mt mt ng sut "5.4.3.1 Mt mt theo thi gian &5.4.3.2 mt mt do nn ngn n hi5.4.4 Lc d ng lc yu cu/5.6.1 Xc nh mt mt ng sut ti im truyn"5.6.2 Mt mt do nn ngn n hiGiai on I: Thi cngGiai on II: Khai thcMu1 =Mu2 =+6.4.1 Giai on I: (Mt ct khng lin hp)&6.4.2 Giai on II: (Mt ct lin hp)5.6.4 Tng cng mt mt 6. Trng thi gii hn Cng 6.1 H s sc khng16.2 Cc h s iu chnh ti trng c th p dng 6.3 Mmen un6.4 Kh nng chu un)5.7. Khng ch nt bng phn b ct thp 6.5. Cc Gii hn ct thp 6.5.1 Ct thp ti a6.5.2 Ct thp ti thiu:)6.5.3 Trin< khai tao cp ng sut trc 6.6. thit k chng ct v xon6.6.1 Qui trnh thit k 6.6.2 Sc khng ct v xon6.6.3 H s lc ct v xon6.6.4 Lc ct c hiu06.6.4.1 Lc ct v xon do tnh v hot ti$6.6.4.2 Sc khng ct danh nh+6.6.4.3 Kim tra yu cu b tr ct ai16.6.4.4. Khong cch ti a ct thp ai chu ct46.6.4.5. Khong cch ti thiu ct thp ai chu ct6.6.5 Ct thp dc7. vng v vng7.1 vng do d ng lc 7.2 vng do tnh ti!7.2.1 Vng do trng lng dm*7.2.2 vng do trng lng bn lin hp-7.2.3 Vng do trng lng g chn lan can%7.2.4 Vng do trng lng tay vn-7.2.5 Vng do trng lng lp ph mt cu7.3 vng khi cng ko7.4 vng do tt c tnh ti7.5 Final Deflection by BMD7.5 vng do Hot tiStandard conditions Long-term deflection: 3 = 19 mmyA(mm)-mwkN/mmm ********** TABLE OF CONTENTSPage 1. STRUCTURE .......................................................................................................................................}.............................................................................................................................4.1 Criteria for Deflection-4.2 Optinnal Criteria for Span-to Depth Ratio4.3 Concrete Cover5. design or main girder5.1 Structural Analysis"5.2 Sumamary of Section Properties5.3 Load Distribution$5.4 Dynamic Load Allowance ( Impact)#5.5 Computation of Moment And Shear6. limit states6.1 Service Limit State(6.1.1 Applicable limit stage factor*6.1.2 Load Combination And Load Factor(mm2)6 has9hpv9gckg/m3 !Ec = 0.043yc1.5 f'c $fr = 0.63 f'c  nr:Ay2Hmm2Hmm3Hmm4Hmm4Id (/ nr)J)mm2IybOytOytdOSbOmm3IStOStdOAsphalt ( gas=21.6 kNm-3)  9  P19P29  Vi Din : O k = 2.5*(Nb)-0.2 II = Moment qun tnh dm ( m4)I m4 J = A4/40Ip=I Din =O Dex9 Where Din-s : 9.Nu Ix <1.7E10 th ly Din-s nh i vi mmenO I Din-s =9Dex-s9M = S Pi . zMi   9  9Q = S Pi . zQi   9  9M = w . FM Q = w . FQ hS(giQi)<=fRn=Rr  7 h = hD . hR . hI > 0.95!"'(-.4hD = H s xt n tnh do ca kt cu  *>hR = H s xt n tnh d ca kt cu  7hI = H s lin qun n tm quan trng khi khai thc hDhRhl f = 0.90 ,f = 1.00 FLEXURE IN PRESTRESSED CONCRETEh = 0.90 SHEAR hD =   hR =  hI = h = hD . hR . hI=  gD =gL =hD =hR =hi = h=hDxhRxhl = h=gD=gL=95.4.1 ng sut cho php b tng trong trng thi s dng:^ ft=0.50 f'c (Mpa) ft=0.25 f'c (Mpa)  15.4.2 ng sut gii hn tao thp ng sut trc ^ DfpES = (Ep/Eci) fcgp9J ng sut trong qu trnh to ng sut trc = P / Ago + P x eo / Sb! %fps = Pi / Ago + Pi x eo2 / Igo =I  ft = - 0.50 f'c = = Pi / Ago + Pi x eo2 / Ig )Dfpr1 = Log(24 t)/40.0 (fpj/fpy-0.55) fpjDfpr1 =Dfpt = DfpES + Dfpr1 =  fti = -0.5 (f'ci) =   => Dng f16 fti = 0.5 (f'ci) =  )fsa = ------------------- 9(0.6 fy9 (dc. A)1/3 2*dc*b / ns 9fsa =9hS(gi Qi) < f Rn < Rr   hD =hR = hI = T hp cc h s h = gas=9gDc=9gL=9hS(giQi) h(gDc*Dc+gas*Das+gL*LL)9  9 99( 0.85 f'c, trn mt chiu cao a= b1 c ."# \ H s b1 s c ly bng 0.85 vi cng b tng khng qu f'c = 28 Mpa. Vi cng  O b tng vt qu 28 Mpa, b1 s gim mc 0.05 cho mi 7 Mpa vt qu 28Mpa, b1 = 0.858b1 = 0.85-0.05(f'c-28)/7 >= 0.65 vi f'c > 28 Mpa$ ' Dng : b1 = / (0.85 f'cb1b+k Aps fpu/dp)   a =b1 x c =Mr=f Mnf =Mr =f Mn >1.2 Mcr(mm3 mmen tnh mt ct lin hp i viI )mm3 Mmen tnh mt ct khng lin hpI fr= 0.63sqrt (f'c)=  !ld ( 0.15 fps -0.097 fpe ) db  Vr = f Vn  Tr = f Tnf =Vu = hS(gi Vi ) Tu = hS(gi Ti ) h =g =H V tr mt ct nguy him i vi lc ct s ly ln hn 0.5dv cot(q)FGE Bi gc q, l gc nghing ca ng sut nn cho, l cha xc nh   " ti im cch gi 1 khong " dv"  ! Vu = hS(gi Vi ) ;  Tu = hS(gi Ti ) ; : Cho t hp lc ct v xon , Vu= Vu2+(0.9*ph*Tu/2Ao)2$%( )0919 mm2 1 Vc = 0.083b (sqrt (f'c) )bv dv O Vs = Av fy dv (cot (q)+cot (a)) /s "#* q = Gc nghing ca ng sut nn cho /Gc nghing ca ct thp ngang vi trc dc, a=-.AGc nghing ca ct thp ng sut trc xin gc vi trc dc, a=?@" Vp=P(HARPED)* SIN (a) =[ b & q l cc hm ca ng bin trong ct thp dc, ng sut ct trong b tng  < tr ln ln hn khi q nh hn v khi Vc tr ln ln hn. ;X Gi tr ca b & q c da trn vic tnh ton cc ng sut c th c truyn qua  9ex = (Mu/dv+0.5Nu+0.5Vu cot (q) - Aps fpo)/(EsAs+EpAps) < Mu = h(gDc*Dc+gas*Das+gL*LL)=9 999 Xc nh b & q Gi s q = ex =:(Mu/dv+0.5Nu+0.5Vu cot (q) - Aps fpo)/(EsAs+EpAps) <0.0029 Gi tr ex l m th gi tr tuyt i s gim bi h s    Fe = Fe . e x == v = (( Vu - f Vp) /(f bv dv))2+Tuph/(fAoh2))2$%- .569 :< ' Th ln 2 vi gi tr q = !g"Q  th ex = Fe xex =   ( Tra biu hnh 5.8.3.4.2-1: q =$%h Vu / fVc =0.083bsqrt(f'c) bv dv =  " Vu > 0.5f(Vc + Vp) 0.5f(Vc + Vp)= mm2 <=> S f(As fy+Aps fps) > [Mu/(dv )+0.5 Nu +cot (q)(Vu-0.5 Vs - Vp)2 + (0.45*ph*Tu/2Ao)2)*+,-= >Q Rq a f(As fy+Aps fps) =A Mu/(dv )+0.5 Nu +cot (q)(Vu-0.5 Vs - Vp)2 + (0.45*ph*Tu/2Ao)2)=* +> ?T bin t 4 ti ngy x103m4I I Pt = ntao*Aps*(0,78*fpu-Dfps)= h= Pe/Pt = 6dt= (Mp*L2 ) / ( 8*Ec*Ic ) = (Pt*es*L2 ) / ( 8*Ec*Ic ) % &de=dt*h=ddo=(5.gdo .l4)/(384.E.J)=9  dcb=(5.gcb .l4)/(384.E.J)=9  drl=(5.grl .l4)/(384.E.J)=9  dpv=(5.gpv .l4)/(384.E.J)=9   Sd=4Sd=4*(dt+ddo+dd1+dcb+drl+dpv)=  Gy(t,ti) = 3.5kc kf(1.58-H/120)ti(-0.118 )(t-ti)0.6/ ( (10 +(t <t-ti )0.6) )/ 2C F.Thay s: y(t,ti) =   -Sd(lu di) =Sd ( ELASTIC )* (y(t,ti)+1) =  Sd = (ELASTIC) * (1+Ct) =dpv=(5.gl4)/(384.E.J) dpv=P.c.(3l2-4c2)/(48.E.J)  dpv)d(Hot ti) < 1/1000 * (khu nhp)= Wd1=Aco*gc=hi Wcb=Acb*gc=0.35*0.5*24.5hi  Wrl=0.04*9.81*10=(Asum. =40kg/m)h# + Wrl=hpv*(girder spacing-0.5)*gch!i" + Wrl=hpv*(girder spacing)*gchi$ + Was=has*(girder spacing-0.5)*gash h !i"h  + Was=has*(girder spacing)*gash h i + Wcip=(sg*hg-Ac)/2*gchih + Wcip=(sg*hg-Ac)*gchihWd2=d*(girder spacing)*gciH ni -6.2 Strength Limit State(6.2.1 Applicable limit stage factor*6.2.2 Load Combination And Load Factor'8. determination of prestressing forces 8.1.1 Tensile stress limits68.1.2 Compressive stress limits after all losses%8.3 Approximate Evaluation of Losses = (Bt-2*50)*(hg-2*40)VuAoh = 2*((Bt-2*50)+(hg-2*40))((EsAs + Ep Aps) / (EsAs + Ep Aps +Ec Ac)8.3.1 Time dependent Losses)8.3.2 Losses Due To Elastic Shortening 8.4 Required Prestressing Force"9. stresses at service limit state10. STRESSES AT TRANSFER 510.1 Determination of Prestressing Losses at Transfer&10.2 Losses Due To Elastic Shortening$10.3 Losses Due To Steel Relaxation10.4 Total Losses at Transfer at point " dv" from Support ! of PAving, asphal and C.I.P 0.42 =>b c tao thp ng sut trc dnh bm s c kho st nh gi theo t hp ti trng S dng-IIIMpa Cng ph hoi gii hn chy Ti u kchTrng thi gii hn s dngSau khi truyn ng sut X Vi b tng trng lng thng thng c to ng sut trc bng thp trng thpU mt mt do t bin v co ngt ca b tng v t trng ca ct thp theo thi gian," ly xp x theo cng thc sau:F Vi dm bn rng vi thp trng thp cng ph hoi 1860Mpa:Trong Do ti trng ln: Do 1 trc xe:C PPR (T s DL tng phn) = Aps fpy/(Aps fpy+As fy) 4 Khi khng DL tng phn, As = 0 th PPR =$ Thay th bng: Tng mt mt = 55 Mpa cho cc dm bn rng.. Cng ton b mt mt theo thi gian =M Mt mt do nn ngn n hi s c cng thm vo mt mt theo thi gian trung tm nc tv v tn cng trnh#h s thit k dm bn rng l =21 mtrng i hc giao thng vn tiCng b tng tui 28 ngyCng b tng khi ct thpcng trnh : XXXa im : XXXXEbn tnh dm bn rng d ng lc l = 21 m - tiu chun 22 tcvn 272-01( Nh hn gii hn ng sut l 0.6f'c 2 ng sut trong b tng ti trng tm cc b cpm E5.6.5 ng sut trong b tng ti im truyn cch gi mt khong "D"p ' ng sut do trng lng dm: Mg =m , ng sut do d ng lc ti th trn dm:m $ ng sut cui cng th trn dm:m , ng sut do d ng lc ti th di dm:m $ ng sut cui cng th di dm:m ng sut cho php  05.6.6 ng sut trong b tng cch gi "1.0 + D"p F ng sut nn c kho st nh gi vi t hp ti trng S dng-Im  ng sut nn trc yu cu:m " ng sut nn trc yu cu =m I ng sut th trn dm trong b tng ti gia nhp do ng sut trc m ng sut cui cng th trn dm:=4ng sut do ti trng thng xuyn v lc d ng lc 2ng sut do tt c cc ti trng v lc d ng lc 6ng sut nn gii hn trong t hp ti trng s dng I +ng sut trc th di dm do d ng lc :=8ng sut ko gii hn trong t hp ti trng s dng III K ng sut th di dm do tt c cc ti trng v lc d ng lc : m O ng sut trung bnh trong tao cp ng sut trc , fps, c th ly nh sau:m 7 ng sut trung bnh trong tao thp ng sut trc :m X ng bin trong ct thp dc pha chu ko do un ca cu kin c xc nh theo:m mm ( k c bn lin hp )$ trong tng cc mt mt ng sut 1.2 * Mcr = =>Reinforcing Bar AreasBardeg.AsphaltMPa Mpa n x n = n x mm xPi = n Aps fpi = =fcgp = fd0g + fps = = n x fpu =N = =fpsmm m2 IM ==z max M, F of inf.=kNMomentShearkN.m Truck  Lane =z max Q, F += F -=  =z max Q,Torsion Ecentric.=z max Q, F of inf.=m2 dv from bea.End11. 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'   '   '   '' *  '  ' ~ W@ ~ W@ ~ &? ' [ffffff? EDDDffffff? DDDffffff?B %% = ' '' ' '' '+ ''' '' ' ''' ~ ? '>o0$.H88@***} 0                                 ''' ~ ? ' ''' ~ ? ' ''' [~ T@ ' ' '' ' '' ''' ' '' ' '' ''' <' ''  ' ~ W@' ~ W@' ~ @Z@' '  'mR? DDD  [ffffff? EDDDffffff? DDDffffff?B'   '' ''' '' ~ ? ' ' ~ ? '' ~ ? 'BfX:::  0&&Um  D4 `                            0     '['\U ECng - I D0.00A0[1.25 DC +1.5Das+ 1.75 LL]41Cng - I 0.95[1.25 DC +1.5Das+ 1.75 LL] =,=' ' }''''' '' }''''' '''''''' '''''''''''''''''''''' '''      '''    b c '''     '''  ΄? D@ /c;@ DD  e ''' sGi@ nD=òA? Co  e0} zDD  '''  ?΄? Cz /=D? DD  e ''' Қ<`]@ D>òA? Co  e0=Je DD  '''   D? Cy /T߶ٟd? DD  e ''' Bmk@ D?;w? Cm  e09=<- DD  '''    D? ! E  /? DD  e '''  Li4@ D@;w?    e0Ny%ÿ DD  '''    D? ! E  / ? DD  e ''' '+@l@ DADBDC;w?   e0}{$ DD  ''' #N"󮤖@  %ز #"}S"C(@ t %ز#vav(  %ز '''   D? ! E /eB]#@ vDD  e ''' G^@ DD;w?   e0 sr( )DD  '''   D? D /Z5Q@ DD  e ''' %gl%@ ?D;w? D  e0(† DD BX  :0&&V`J   , Y             Y            q- pU ZCW B;****************** SKIP THIS SECTION ********************** B < =. ' 'V ''' 'Q ''' ' ''' ' 'W '' 'X' =/ ' 'x ''' ' 'Y' ' 'Z 'z <' ' '' ''' ' S '' @ C0 R' T U%(@ ?C0 R' U "%̕@ c ?C0 R' W #%X@ ffffff?C0 R' V T%@ ?C1 R <0< =1  ' < t&&& &&&&(a]]]] 4       ;              'X 'Y 'Z   '[  ''''''' ' '\''''''' '_''''' '`''''? ' 'a ''BDJs@ ,333333?C))))D ' '' ' '''''' 'b '''''' 'c ''' DJ^p@ R D7 ' ' 'd '''''' ' '''''' =2 '''''''' ''''' '<''' z['=@ C* ' ''' z\<O@ ]&jt?C6?DA@ ' ''' z]'@ A C$ '' '_''''' '' '^'''' 'b'''''' '`'''''' ''' z%'X@ Wffffff?C0 ' ''' z%'3333[ A DfffffVa@ ' '' 'a''''' 'c''''''r'U \- khi gi thit tng cc mt mt ng sut l D 0A0 Mpa cho ln lp u tin.MJ khi gi thit tng cc mt mt ng sut l 262 Mpa cho ln lp u tin.'''''' '' zdDJ^p@ &D  '  ''@4 D&2$,G~$$Y$$$:MlK,.$$Uc,$ !"#$%&'()*+,-./0 1 2 3 4 5 6 7 8 9 : ; < = > ?  ''''''' !<3!'''''' "'"'''''' #'e #'' #'j #'' $'g $'' $h~ $'G@ $'f$' %'"%' %i %''' &''' &[6&'-H߂ܥ@ - @D$(\?C0D &'#&' ''k''''''' ('' ('$('''' )''!)52 + DD )' )''' *'y*'''''' +'' +'%+52 ,D) +' +'' ,'z ,'',52@ cD+ ,' ,'' -'n -''%-5@ /333333?C) -'m-' .'n.''''/' /'l/'/'5@ 0D- /'/' 0'o 0''052 3D+ 0'0' 1p1''''''! 2'' 2'q2'''' 3'' 3's3'3[@ 4DP 3'i 3' 4'' 4'r4'%4t{_rs@ 5CD3 4'i4' 5'' 5'F5'Cc@'? 50D&C D&D4Co   5[552 6D+ 5' 6''' 6'&"6B@ ? D5D5 6'u6' 7''7' 7't 7'&'7'A@ LDMDNDO 7'u7'8'''''''9''''''':;<=>?? Jێz@ @ CD l$$8P6p$.Q$WX] YS(.cg\w @ABCDEFGHIJKLMNOP Q R S T ;U V ,@W X Y Z [ \ ] ^ _ @@@ 2<}@ A CAA !7$z@ B CBBB Ng|#~@ C C~CC 2<}@  CDEFGG`@ HH@ GIJJ t KvK''''''' K ''t L'w L''LA@ fD7L'''' L ''t M'x M'''~ MF@ M'~ M 0@ M'u M '' M u8Uㅛ@ D N'x N'''~ NV@ N'~ N0@ N'u N ''t O'x O'''O@ P C=2 O'~ O @ O'u O '' O u` jD P'y P'''qP[@ Q[DM;DMDMDNDNDODODMDNDOC?CB P'i P'' P ''t Q'z Q'''%Qt{_rs@ ~CDP Q'i Q'' Q ''t R''' RzdRDJ^p@ ^D  R' R'' R ''t S'{S''''''' S ''t T'' TT''''' T ''t U'''''''' U ''t V'oV''''''' V ''t W'' Wz'WgffتPA XD7CD W W''' W ''t X'' Xz)Xgz@ YDW  X+ X''' X ''t Y'' YzHYwDW-/@ [2DXCDXDQ CB Y Y''' Y ''t Z'' ZzFZ \E+@ {DqDD v' v''' v ''t w' w w''''' w ''t x'' x'x'''' x ''t y'' yz.%y/@ {?C) y{9y{`U y#DyDt > <B>y3W\zf@ yDtTydU >DyDt  Mpa OK !  Mpa Check !B Mpa OK ! y ''t z'' z'z''{' z ''t {'' {z/%{5@ 333333?C) {{9{{U {#D{Dv > <B>{>\E+@ {DvI{U 3DyDt  Mpa OK ! Check !B Mpa OK ! { ''t | |'''''' | ''t }'' }'A}'''' } ''t ~'' ~ [C~O!%0@ -DmCDmDQ Co ~' ~''' ~ ''t  ''''' ''  ''t Dl@wsos**~666*@6>o>u>@5@&6@                                ,     (-“ C)A  t ''''''  ''t '' z'pD(  DDD~ { {  ''t ''  ' t''' t '' " #$  ''t  b cv  1  1!v  v  c;@ qD} Dv  =D? D=Je Dv  T߶ٟd? D9=<- Dv  ? DNy%ÿ Dv   ? D}{$ Dv   eB]#@ D(† Dv    !"-I DqO!%0@ D~v  # $%8Uㅛ@ M $D%Կ @ $lDv % &v  # $#>\E+@  %#` O %v ' ()v  *+v  # $(ŭ۶B C*A/@ Dyv % &OU 9DD  OK!Required Bond controlBOK!OU 9DD  OK!Required Bond controlBOK!v  # $5@ D{-“ Dv ''' ()OU 9DD  OK!Required Bond controlBOK!OU 9DD  OK!Required Bond controlBOK!  ''t ''''''''  ''t q pU ZCW B;****************** SKIP THIS SECTION ********************** B t t  t  t  ' tD&lR6u>"@DD8zzzzz||888|*~       @   ;            ,            2Ї@  <D i ~ ؓ@  i t <4 t t  t t t <5 t ' '' t ''  t t z=@ C*  t z\O@ C"  t z]@ A C$  t '_' t' '^ t 'b' t '`' t '' %X@ ffffff?C0 3 t '' ) t '' 'gffتPA D7CD )gz@ D  + t   t HwDW-/@ 2DCDDQ CB  t t  E B>{U"+(@ DY.U CDD ! Require Bond Control  OK !B  OK ! t'   t    t   t /01 23 2 45 t 6 7Eܼ&?$D98Z$<$D : t 6 7 H} $D98)=Vd*@$D : t 6 ;#'[$ %9#8{U"+(@$ % : t v <ŭ۶B$DB=U ,DD  OK !CHECK !BOK !>1@ DS?U =DD  OK!#Required Bond control !!!BOK! tS@AB tpCU$ZD@D@  OK!@6 Reinforcement required is : As=( 0.5 ftop*c*b/0.5fy )BOK!   t qD [D@D@ DDC?DADDACaC3B EF2G DAA  t CHG t <w t t~ @ ' t!@  DD '  -t  t ' ?yDZLA )CWDC(\?C0D I)J;ua{*@ D  '+ t 'qGV34A 1D= DDD  t ' /R&bV@ DCz "  KLM  t ' 0t DCo "  t 'r t B t [ C,j  -DCDD Cz   t 's ! ~  DD  t ' tDlR6{6*062N|| $, &C{yh""Y                               ,     ;  ,    ;    (ŭ۶B C*A  t 't t D t [AͰd.@ +DCDD Co  t 'u !u?:)@  DD  t~   ' t %1@ 333333?C* :U $DD   > <B >u?:)@ DDN U .DD   OK !Check !B  OK ! t   t    t     t /01 2 3 2 45  t 6 O R&bV@$ D  t$ D P  t 6 O ,j $ D  Ͱd.@$ D P  t 6 Q#  ~$  %   # u?:)@$ %   P  t  RSTŭ۶B$DBUU$,D D  OK!CHECK ! BOK!V1@ D?W$U )D D  OK!CHECKBOK!* tS@XB tpY,U$ZD D  OK!@6 Reinforcement required is : As=( 0.5 ftop*c*b/0.5fy )BOK!  t qZ [D D DD C?D AD D ACaC3B EF2G LDAA  t' w B =}[4U gCOH y l kt cu BTCT ng sut trc , khng phi kim tra theo mc ny BKH y l kt cu BTCT ng sut trc , khng phi kim tra theo mc ny ' ' \   ']  bSH@ =DPDU 2 2DPDU B  '  ' c  ' dG 1DU DCaDUB  ' @@ "Ca  DE lRkq (62N|| $, 4"*u  ! " ; # $ % & ' ( ) * + , - . / 0 1 2 3 4 5 6 7 8 9 ; < ;= ;> ;?   '! !e~ !v@ !f ! "M"\ "7DU "D!DDB "g "h%"o@ #333333?C3 " #-]S#U =D"D"?  => OK! => CHECK !B  => OK! $q=$  %= &' '' () *<> +^~ +V@ +' ,^~ ,? ,' -^~ -V@ -' .^ /<? 0 1~ 1W@ 2^~ 2W@2 3^~ 3@Z@ 4z[4ffffff? =ED3D2D1ffffff? D3D2D1ffffff?B4 55 6q@6 7< 8' 9' ;'; ;' <^<&? >D <' =^=? <D =' >^>? BD >' ?'? ??B/XBu ***&w &;;;@ ;A B C D E F G H I J K L M xN xO xP Q R S T U V W X Y Z [ \ ] ^ _  @'@ @_ A6 A' A8@A8uC@ h*D4@D=D=D>D?DADC A B7 B B9OBR>K@ v9D4@D=%=A@@8DC@D<DB@D>D@ BCC D<A E' E' F' G' H'Hx I'J' JJ J'K' KL' L'9L&? <#333333??C)=LU L'DL? > <B>L? N ?L t M`MaMaM`M y N`a NbNc@ WC0 NxNa N'N yO` OxOd0OcQ? ^p= ף?C1C0Oa O'O y P'P t Q'Q Q Q' R' Se:Sf T T Ug9@ V V0V LDUDU# Be V W`W Y W X!X7@ V CWC X XY YY@@ aCa Y Y Z%ZKKKKK@ 7CC Z Z Z [ [[ \_/\@ eC=D;DU \ \ \] ]] ^' ^d^6,@p@ aNDXC0CC3333333?C)DLCDODXC0DZ ^i ^^ t_' _!_ͦi@ \ DLD^ _iD; l&|06kx4^9OSa&k"` a b @c d e f g h i j k l m n o p q @r s t u v w x y z | } ~   `'` ta' a2aVX;@ gC0DOD^DZ aa@ hC0 aa t b'b t c'd' d d^e' eWeh"ӽYA eADXDaDZD_@DVC3D\D_@ e #e&î@ h De  e f' g gZg&? _D??CCWC/CCWC/CC3 g' h !hî@  DgDeLhiU$i6DhDB  kN.m > Mu= kN.m < Mu =B kN.m > Mu=hih8uC@ )DA hiiiKiU 5DhDB => OK! => CHECK !B => OK!i je; jf k+kKKKKK;@ mCCC k k l_!l@ s CC l lm' mvm}{Hr@ p`CWCC0CC3333333?C+DLCaCVDOCWCC0Dk mi mm tn' n!nÕ@]m@ l DLDm ni o'o tp' p2pB-@ nC0DODmDk pp@ AC0 pp t q'q tr' r r^s' sYshB7A[,A vCCCWDpDkDnCC3DlDn@ s #s&̳Q&@ v Ds  s t' u uZu&? sD??CCWC/CCWC/CC3 u' v !v̳Q&@ p DuDsLviU$u6DhDB  kN.m > Mu= kN.m < Mu =B kN.m > Mu=vivR>K@ kDB vKvU v5DhDB => OK! => CHECK !B => OK! wqCw x= y<Dy z' |  |' }'} ~  ~' '!B X&{[QK&(                                 ' '' '' z6,@p@ D^ i za '' '  '' ' '' `jKKKKK@ JCWCC/CCC3CCWCC/CC3 i !rkE?  DD=,U 'DzG? < >B< PC.0U -DzG?  OK!CHECKBOK! k <E  ' ' '   '  lm;w? Cm ' 'n ' 'n' lnòA? Co '' ''' (vA) @ )\(?C)A   ' O!%0@ 2C- '' A@ C) '' sGi@ CQ ' '  MZv@ 7DDDCQ DD !#M/@  D   %Xk@ 333333?DC8U -D333333?D < >B<î@ zDh  Bp<U ,DD  OK !CHECK !BOK !o  <F t ' t ' t'   ' tB XI&&&&*;;&dEEI,               ' "VX;@ Da  t' #+ my@ (\?C0CN  t' $~ ؓ@ i t '<4yq@ &333333?DEԸ?DD \b; ?  D f t t qG 4q  <H ' ' ' ' ' ' ''' %@ DK i '&#r@  CO iJrHU 4DD > 2 * d=<2 * d=B > 2 * d=@  D iy\U cDD &=>S dng m hnh mt ct phng)=>S dng m hnh chng - gingB"=>S dng m hnh mt ct phng  <I    ' ~ V@ ' ' '' <J   ^ffffff? D4 ' ' ^&? D< ' ' ^&? D= ' ^&? D> ' <K ' 'BXO_>8 E8J""WIE;              w@ w@ w@w@w@w@w@w@w@w@w@' ' 2 r[%٨q@ DD_ 3 4%˄@ ?D 3 I5#`@  %B i 6%`@  ףp= ?C? 3 '' '' '' ''' z`@ D i =L =' ' ''  7Is;>0@ 3DD%=ADDBDDD  ''  8JsIUX@ 4DD%\`uDDaDDg  ''s AZ+ @ DD?DD 333333?DA  's s& B @/p%A CdC?(  B C4h@ CdC?( i =M '''''''' ''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' 9 ' : ' z' ''  ' ''DO lOEE "**"AF"                                '' ' '' ''' z~ V@ '' 'x '' z  '   '  ' ' ' ' ' ' ' ' '  ; ' t < ' t =5&_%@ DCDDC? > t ' '' t ' '' t ''' t '' E,+ my@  (\?C0CN  tU U ?(0.78*fpu-E545)*(dv+CJCO0A0 )/(60*12.7)%"(0.78*fpu-E545)*(dv+200)/(60*12.7) '' t '' t F-/f2汑@ DDC$C!  t ''''' t ''''' t '`@ C'U  mm cng vi CJCO0A0@& mm (khong cch t gi ti u dm)=DCJCO0A0@ mm A> mm cng vi 200 mm (khong cch t gi ti u dm)=884 mm '' t'zdU tCCJCOD (! ln hn chiu di truyn D = +! ln hn chiu di truyn D = B$! ln hn chiu di truyn D = 'Ї@ Do'U YCCJCOD mm, => fpo s bngmm, => fpo s gim iBmm, => fpo s bng' 'Gj/f2汑@ TCCJCOD  $*DDCJCODB ''BS X&:"Q9>&i&&""W**&k ;  ,         ,          '''  '' ' ''' ' HSđ[@ =D=D DD   ' S.;@<@ =D?D DD   ' S|-*@ =D@D DD   ' SQ@ =DAD DD   'LAfYh!@ DB  ' SLAfYh!@ =DBD DD   9ӌ v^@ DD tu - O bHy@ 9DD%PDDDDD  o '  ' S( @ CWDC  '  ' '' z~ ;@ ' ''   '' ([y@gi cD  C?D DAVAD DC$D C%C ''! '''   D !! '' [b ? LC%CC$D C%CC$D C!CaC~  !!  "h#o#z?  DDIIU 3DMb`? < 0.002>0.002B < 0.002 ''   % '' [uku!? _D C,DC,CaDD DC,DA  % '' !ޥ/? ! DC) & % ''  ~ ;@ ' '' z z@gi {D  C?D ?D DAVAD DC$D C%C '' z$z#o#z? DADPU C:DMb`?  <0.002>0.002 => Use B <0.002 '' z~ ;@ ' ~ `@ =N zz z D lC(sss;sYR8*"B0YL8  ! " # $ % & ' ?@( ) * + - . / 0 1 2 3 5 6 7 8 ,9 : ; ,< = > ? , ' zz {!' !H!4^D@ #2sh|??DC)ADCa  !! !' "'"#' #N#4^D@ $8sh|??DC)ADCa D # #% #'#  $'$lE$5@ %/?C)DC? 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